nijayatwitty
nijayatwitty
09-06-2018
Mathematics
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I need help with this
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gmany
gmany
12-06-2018
[tex]x=9\to9\leq x < 13\\\\\text{therefore}\\\\f(9)=12[/tex]
[tex]f(x)=\left\{\begin{array}{cccc}6x^2+2&if&-6 \ \textless \ x \ \textless \ 9\\12&if&9\leq x \ \textless \ 13&\leftarrow\text{here}\end{array}\right[/tex]
Answer: 12
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