A car moves from the point (3.0 m)x^ + (5.0 m)y^ to the point (8.0 m)x^ - (7.0 m)y^ in 2.0 s. what is the magnitude of the average velocity of the car?
8.0-3.0=5.0metres in the x direction 7.0-5.0=2.0 metres in the y direction Use Pythagoras 25+4=29 [tex] \sqrt[2]{29 } [/tex] =5.39metres in 2secs =2.645m/s at an angle of 68.2 degrees to horizontal.... see below! tan-1 angle = 5/2 angle=68.2 degrees
