Respuesta :
1n + 4n +16n^2 -6n = 4n -6
16n^2 -n = 4n -6
16n^2 -n - 4n + 6 =0
16n^2 -5n+6 =0
Now we have the forula for finding n
n = -b+-[tex] \sqrt{b^{2} - 4ac} [/tex]/2a
n = -(-5)+-[tex] \sqrt{(-5)^2 - 4*16*6 } [/tex]/ 2.16
n = 5 +-[tex] \sqrt{359} [/tex]/32
n = {5 +/- 359i }/32
