jenkiada000
jenkiada000 jenkiada000
  • 08-05-2018
  • Mathematics
contestada

Which solution to the equation (1/x-1)=(x-2/2x^2 -2) is extraneous?
a. x=1 and x=-4
b. nether x=1 or x=-4
c. x=1
d. x=-4

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 08-05-2018
Any "solution" that makes a denominator zero will be extraneous.

The appropriate choice is ...
  c. x=1

_____
This can be solved without extraneous solutions by subtracting the right side.
  (2(x +1) -(x -2))/(2(x -1)(x +1)) = 0
  (x +4) = 0 . . . . . . . . . . . . . . . . . . . . . multiply by the denominator
  x = -4 . . . . . . . . . . . . . . . . . . . . . . . . subtract 4
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