Answer is: the volumes at standard temperature is 1639.46 L.
V₁(gas) = 2240.0 L.
T₁(gas) = 373 K.
T₂(gas) = 273 K, standard temperature.
V₂(gas) = ?
Charles' Law: The Temperature-Volume Law
- the volume of a given amount of gas held at constant pressure is
directly proportional to the Kelvin temperature:
V₁/T₁ = V₂/T₂.
2240 L/373 K = V₂/273 K.
V₂ = 1639.46 L.
