Consider: Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s)
How many grams of excess reactant do you have if you react 221 grams of Cu with 2.70 mole AgNO3?
Molar masses:
Cu = 63.546 g/mole
AgNO3 = 169.87 g/mole
Cu(NO3)2 = 187.56 g/mole
Ag = 107.868 g/mole
Part A. Limiting reactant is AgNO
Part B. Excess reactant is Cu
Part C. There are how many
grams of the excess reactant left over.