A foot of the normal from the point (4,3) to a circle is (2,1) and a diameter of the circle has the equation 2x−y−2=0. Then the equation of the circle is:
(A) x² + y² – 4y + 2 = 0

(B) x² + y² – 4y + 1 = 0

(C) x² + y² – 2x – 1 = 0

(D) x² + y² – 2x + 1 = 0