sibusiso1919 sibusiso1919
  • 09-01-2024
  • Chemistry
contestada

If z equals 1 iota into 1 2 iota and so on up to 1 upon 1 minus iota 2 - 8 up to n minus iota, then the principal argument of z can be:
a) π/2
b) π
c) 3π/2
d) 2π

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