Given that \( y_{1}=e^{-x} \) and \( y_{2}=e^{5 x} \) are solutions to the homogeneous equation \[ y^{\prime \prime}-4 y^{\prime}-5 y=0 \] find the solution \( y(x) \) to the initial value problem with y(0)=5 and y ′
(0)=3. y(x)=