Answer:
5/12
Step-by-step explanation:
A coin has two faces (H, T)
n(S) = 2 (sample space)
If it is tossed and a rail is gotten,
n(E) = 1 (event)
Probability of tossing a tail = n(E)/n(S)) = 1/2
If a dice is rolled, the sample space S = {1, 2, 3, 4, 5, 6}
n(S) = 6
Number greater than 1 are the evens E = {2, 3, 4, 5, 6}
n(E) = 5
pr(rolling a number greater than 1) = 5/6
Hence the probability of tossing a tail and then rolling a number greater than 1 = 1/2 * 5/6
= 5/12
